From the given data,values of d are got as follows:
- 22, - 1.2, - 2.5, - 1.7, - 2.6, - 1.8, - 2.2, - 1.2, - 1.9, - 2.4, - 2.3, - 2.3, -0.9
From the d values, the following statistics are calculated:
.n =13
- 25.2/13 = - 1.9385
sd = 0.5485
SE = sd/
= 0.5485/ = 0.1521
= 0.10
ndf = 13 - 1 =12
From Table, critical values of t = 1.7823
So,
Confidence Interval:
- 1.9385 (1.7823 X 0.1521)
= - 1.9385 0.2711
= (- 2.2096, - 1.6674)
So,
the confidence interval is:
- 2.21 < < - 1.67
This Quiz: 14 pts poss Question Help ng the re ulity a nh'a. gthat is reported...
Question Help Construct a 90% confidence interval, using the inequality ä- to To<Ha <atte Th To test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night, researchers randomly select 13 patients and record the number of hours of sleep each gets with and without the new drug. Patient 1 2 3 4 5 6 7 8 9 10 11 12 13 Sleep without the drug 3.4 2.4...