Question

Hi everyone! Can someone do part c) and give me an explanation on it? Could you also do a) and b) too. Thanks!

8. (18 pts) A microwave oven uses a klystron to make the radiation used by the oven. Your microwave oven produces radiation with a wavelength () of 1.56 cm. a) What is the energy (in J) of a single photon of wavelength 1.56 cm? b) What is the frequency (in s') of that photon? c) You place some ice at 0.0°C (the melting point of water) in your oven. You turn the oven on for 8.9 seconds and find that 4.57 grams of the ice has melted (temperature is still 0.0°C). How many photons of = 1.56 cm were absorbed by the sample to melt the ice? AH = 6.006 kJ You know: H20(s) → H20 (1) The specific heat of H20(s) 2.108J gºc! The specific heat of H2O(l) - 4.180 J g'ºc! The specific heat of H2O(g) -1.863 Jg'oc!

Answer 1

9 En = 6696x15347 3x108 1.568152 - 11.27x1023/ & actrequency). I = 3x109 11.9231010) 6 5 1.568152 Holy - thold) o. c o. SH. 6.006ks [this i for 1 mol = 18 q ice 7 4.57 q ice For oH = E= 6-006X 4.57 1.5248kJ - 1524.8 R. E nhe 1524.8= nx 6.626x105 X 3x108 [na no. of Photory) 1.568162 na 1.20x1026 photony