Question

please show me a sep wise solution for these problem as i am trying to learn from your solution. if you cant or you answer partially dont answer please.

Question 4 (4 pts): A thin ring made of iron has an inner diameter of 1.00 cm at room temperature (25.0 C), but it needs to fit over a rod that is 1.05 cm in diameter. What you should do to the ring? Note that the coefficient of linear expansion of iron is 1.20x 10-IC, and the melting point of iron is 1808 C a) Heat the ring to 570 C b) Heat the ring to 780 C c)Cool the ring to-38C d) Cool the ring to-170 C e) Give up because it will melt before it fits over the rod Question 5 (4 pts): For a Camot engine, whose cycle is shown on the right, we found that QQ TWTWhat does that mean P for the change in entropy during one complete Carnot cycle, TL T e) Not enough information is given to evaluate As

Answer 1

4. In order to make the reing fit over the reod, we must expand the ring's diameter kom 1 cam to 1005 an. i.e. 4D = 0.05cm. know and expansion in diameter we AD = D. AT Here, Do = Original diameter & tcm a - 1. 2X1 OT = I final - Tinitial given , Tinitial = 2500 we need to find I final. 0.05 - 1 xd. 2x105 (Ty - T ;) Is - 25 = cos c 1.2xlors → Is = 419 1.6706. The iron temperature will option this melt ces before in reaching correct.

110 - we also know the change entropy, as - e i change in entropy at source, and sink, change in enten entropy at asz ott - Substitute ② and ③ in 0 :- 454 - As =0 nie. Net change in entropy over a complete cycle, as=0 Coption to