Question

article with acharge of 1.0 pC "d a masof3.0 ×106kg is released from rest at point A and accelerates toward point Be among there with a speed of 39m/s. The only force ating on the particle is the ele tre foot (a) Which point is at the higher potential ● point B Give your reasoning Negative charge accelerates from a lower potential to a higher potential Negative charge accelerates from a higher potential to a lower potential (b) What is the potentialdifference Ve- Va between A and B dditional Materials Section 192

Answer 1

answer ) a) the correct option is point B

reasoning -negative charge particles accelerates from a lower potential to higher potential.

b) here the mechanical energy is conserved which means

$\Delta$k+$\Delta$u=0

$\Delta$k=-$\Delta$u

$\Delta$k=1/2mv _b²-1/2mv_a²=1/2mv_b²( since v_a=0)

so $\Delta$k=-$\Delta$u=-q$\Delta$v

$\Delta$v=-mv_b²/2q=-3*10^-6*39²/2*-1.6*10^-6=1426V

so the answer is 1426V