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Score on last attempt: 5.3 out of 8 (parts:2.67/2.67, 2.67/2.67, 0/2.66) score in gradebook: 5.3 out of 8 (parts: 2.67/267, 2.67/2.67, x o266) Watch the video and work the following problems. This video is by Khan Academy covered by the Standard YouTube License. Finding mean, median, and mode | Descr..9 Watch later Share Mean, a Find the m M n, and mode 23, 29, 2Mode1 ,33, 25 Khan Academy Find the measures of center for folowing. Data Frequency 60- 64 65-69 70-74 75 - 79 80-84 85-89 90-94 95-99 100-104 12 17 15 mode 82 median 82 mean(round to 4 decimal places) Hint: Textbook Measures of Center Submit Question 10. Points possible:8 Unlimited attempts. Score on last attempt: (2.67, 2.67, 0), Score in gradebook: (2.67, 2.67, 0), Out of: (2.67, 2.67, 2.66) Message instructor about this question Score on last attempt: 7 out of7 Score in gradebook:7 out of 7
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Answer #1

The formula of mean for frequency distribution is as follows:

ar x =rac{sum_{i=1}^{n}f_{i}*x_{i}}{sum_{i=1}^{n}f_{i}}

Let's make table in excel:

60 65 70 75 80 85 90 95 100 124 134 576 924 1394 1305 64 69 74 79 84 89 94 62 67 72 L= lower limit U Upper limit x mid value of the class f - frequency. 12 17 15 82 87 92 97 102 97 306 5504 10 104 67 12 13 14 82.1493 This is the final answer.

The formulae used on the above excel-sheet are as follows:

2 60 3 65 4 70 5 75 6 80 7 85 8 90 9 95 10 100 (A2+B2)/2 (A3+B3)/2 (A4+B4)/2 (AS+B5)/2 -(A6+B6)/2 (A7+B7)/2 (A8+B8)/2 (A9+B9)/2 (A10+B10)/2 -C2 D2 C3* D3 C4 D4 -C5 DS C6* D6 64 69 74 79 84 89 94 L= lower limit u = upper limit xmid value of the f frequency 12 17 15 -C8 D8 -C9* D9 -C10 D10 104 -SUM(D2:D10)SUM(E2:E10) 12 13 =E11/D11 This is the final answ

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