Question

Complete the following table of data for Cez(SO4)39 H20. (Assume the density of water is 1.00 g/mL.) T(°C)| Solubility (g/100. g) Concentration (M) AG (kJ/mol) 7.62 35.0 43.0 6.21 4.0 51.0 59.0 67.0 75.0 | 83.0 5.03 4.10 400 3.40 2.934 2.71 497 4,07 Use a graph of AG vs. T to determine the following. (Enter your answers to three significant figures.) What is the value of AH for the system? K]/mol What is the value of AS for the system? J/mol K

There is no graph that is provided you are supposed to make one with the chart but I am unsure how to find concentration, Ksp, and DG with the given.

Answer 1

G H N Tin kelvir delta G 310 17.7 317 20.5 23.4 26.4 29.3 345 Y = 0.3985x - 105.69 R=0.998 352 34. Series - Linear (Series 1) 300 310 320 330 340 350 360

mass molanty of solure molar mass of volume a soutien (ind) ebro, quo Assume volume of solution 2 volume of water 100 ml solution Contain 7-259 d solve II (10oom Solution contain 72.5g of solure) 5-03 molar muss of cecsay ate 730 5573 g/mol. Solubinky Concentration (m) 7.25 7259 x 0-0992m. 730-55739 m 6.00 6o.59 x = 0.0828 m. 730-55739 m) 50-3/730-1739/ma) 20-0689 m. 4- 20 42-0/730-59739 nel 20.0575m. 3.5 o 00486 m. 3-08 00422m. 2-79. 0.0382 m. (weight has a significant figures, so answer should have a significant figures) cecsand you e acet3 +350-2 Consider Solubiory of ce soit as then (co+3) 2 25, [so2 2 35. is a [co +32 (so, 2) 3 I [25] [3575 - 108 SS. ce csap gives a cot3 nons and 3 so- nons that why [cet3) 225, [san] 235.

change Tc to I ink by adding 2732 - we have soublilty value in m measue kesp using to Kap 2 1088 and the measure AG 2 - RT lhkso where Ra gas constant : 8.314 Ilmatie z 8.314x10 kJ/mol-k. T(Ink) kse (37°c)na3|3101 1 08 60-69923 104 x 18 17:20 Cuyo (7273 a 17k. 108(o. 0828) 4-20x10" / 20.00 Cold +273 324K lof (0-0689) = 1.68 x 104 23.400 S8+273 | 331k 108 [0.0575) z G.79x 105 26.4 6. 65+2733381C 108 Co-048675 2 2.93 x 10 29-30 72+27 8451 108 [0.0422) z 1-45 x 105 32.00 79 +277 3521 108 [o-0382 2 8.78 x 106/34.1k our BH-TOS OG 2 – Tas tot when we draw graph of sh ust we ger slope & -as and intercept a SH. I got eavation of line - y 2 0.3985 x 105-69 OH = - 106 KT -as 2 0-3985 g/mol L AS -0.39&_xml as z - 398 Ilma l