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and me 17) (5 pts) Calculate the pH of a solution that is 0.15 Min ammonia (NH3) and 0.40 ammonium chloride, given the ioniza
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It) pon - pko + log [84t] [B] [84+) [Nuts]= 0.40m (B) - [43] = 0.151 pko = -log K6 = -log (1.76x109) = 4.15 :: POH = 4.76 +

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