What is the molarity of an aqueous solution that is 6.16 % NaCl by mass? (Assume a density of 1.02 g/mL for the solution.) (Hint: 6.16 % NaCl by mass means 6.16 g NaCl/100.0 g solution.)
Answer -
Given,
aqueous solution is 6.16% NaCl by mass
Density = 1.02 g/ml
Molarity = ?
Let the Volume of solution = 1 L
We know that,
Density = Mass /Volume
Mass = density * Volume
So, mass of 6.16% NaCl by mass = Density of solution * Volume
mass of 6.16% NaCl by mass in 1 L (1000 ml)= 1.02 g/ml * 1000 ml
mass of 6.16% NaCl by mass in 1 L (1000 ml)= 1020 g
Also,
percentage concentration by mass of NaCl Solution = 6.16%
i.e. 6.16 g per 100.0 g of solution
So, mass of NaCl in the sample = percentage concentration * Total mass of solution
mass of NaCl in the sample = 6.16 g NaCl /100 g * 1020 g
mass of NaCl in the sample = 62.8 g
Now,
Molarity = Moles / Volume in L
Also,
Moles = Mass / Molar Mass
So,
Molarity = Mass / (Molar Mass * Volume in L)
Put the values,
Molarity = 62.8 g / (58.5 * 1L)
Molarity = 1.07 M [Answer]
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