here we find the frequency of which are exceeded ed by 6 items. therefore first we know from histogram that the frequency of interval 6.5-7.5 is 6, and fro 5.5-6.5 is also 6, now we take half of frequency for 2nd interval to make interval 6.0-6.5 for simplicity just average.
therefore frequency exceeded by 6 items is 6+3=9.
uring one shi the express ane c enk recordeo T or moce items," just items o...