Question

Previous Problem List Next (1 point) If X is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases: (a) n=6, p = 0.3 u = m2 = (b) n = 5, p = 0.9 u= OP = 0= (c) n = 4, p = 0.3 u = m2 = (d) n = 3, p = 0.6 u = OP = =

Answer 1

Date Solution , a) Given that, n = 6 p = 0.3 Using Binomical distribution, 9= 1-p = 1-0.3 - 0.7 Mean - - Их Р - 6xo. 3 - 1.8 Standard deviation =6=√nx pxq - 6x0.3x0.7 =1.1225 Variance - nx P x 9 - 6x0.3 X 0.7 - 1.26 b) Given that, na 5 p= 0.9 9 - 1-P 1-0.9 0. Mean = u = nxP = 5x0.9 = 4.5 standard Deviation - 6=nxpxa = 5x0.9 Xool = 0.6708 variance = nxPx9 = 5x0.9 X 0.1 = 0.45

Page No Date Given that P 9 = 0.3 = 1-P = 1-0.3 -0.7 да их Р = 4x0.3 - 1.2 Standard Devication = nxpxa - J4*0.3 = 0.1965 0.7 = 4x0 .3 x 0.7 Variance = nXP x 9 = 0.89 d) Given that, n=3 p=0.6 9 -1-p -1-0.6 -0.4 меет 2 ц: Пхе - зҳо. 1.8 standard deviation = nxpxa ✓ 3X 0.68 0.8485 0.4 Variance = nxPxq = 3x0.6 X 0.4 C0-72