Question

The figure below depicts the absorbance of the antibiotic Ampicillin at 610 nm as a function of its concentration (in pg/mL). The equation for the line of best fit was: y = 0.01054x + 0.1606 Determine the concentration of an unknown sample of Ampicillin, if its absorbance at 610 nm was 0.350. 0.5 0.45 Absorbance 10 25 30 15 20 Concentration ug/ml Select one: O a. 5.79 x 104 pg/mL Ob. 17.0 pg/mL O c.0.164 ug/mL O d. 18.0 pg/mL

Answer 1

thanks and hope you like the answer

Yanis Y Y ug/mL) Absorbance m=slope m = x Units of me (dag /mL) Mg/mL X-anie concentration (Ag/mL) straight line equation Y = mxtc. Absorbance is takes on y-anis and concentration is takes on x-ans- so for unknown ya 0.350 then x = ??. y = 0.01054x + 0.1606 Sm = 0.01054 Rug/mL) 0.350 = 0.01054 X+0.4606 0.350-0. 1606 = 0.01054x 0.1894 = 0.01054 X x = 0.1894 = 17.97 0.01054 18.01 x = eig(m L e. answer is @ 18. 0 ug/mL a x = y-c - 7 no units. for y' and "C" m 97 * 18.01 20g/m2 -