Question

A buffer containing acetic acid and sodium acetate has a pH of 5.55. The K, value for CH3CO,H is 1.80 x 10. What is the ratio
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Answer #1

For acetic acid


K = 1.80 x 10-5

pk = -log10K, = -log101.80 x 10-5 = 4.74

CH3CO pH = pka + log10 CH3C02H

CH3C0 5.55 = 4.74 + log10 CH3C02H]

5.55 – 4.74 = log10 CH3C05 CH3C02H]

CH3C0 log10 CH3C02H] = 0.81

CH3C0 [CH3CO2H] = 100.81 = 6.46

Take reciprocal on both sides

[CH3C02H] 1 = 0.155 [CH3C07] +6.46 = 0

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