Question

s A company bought a machine for $4,000 that has an estimated salvace value of $1,000 at the end o -year useful life. Compute

the life of the machine is 6 years
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Answer #1

(a) DDB method

SLM depreciation rate = 1/Useful life = 1/6

DDB rate = 2 x SLM rate = 2 x (1/6) = 1/3

DDB depreciation schedule as follows. This method ignores salvage value.

DDB
Year Beginning-of-year Book Value ($) Depreciation Rate Annual Depreciation ($) Accumulated Depreciation ($) End-of-Year Book Value ($)
1 4,000 1/3 1,333.33 1,333.33 2,666.67
2 2,666.67 1/3 888.89 2,222.22 1,777.78
3 1,777.78 1/3 592.59 2,814.81 1,185.19
4 1,185.19 1/3 395.06 3,209.88 790.12
5 790.12 1/3 263.37 3,473.25 526.75
6 526.75 1/3 175.58 3,648.83 351.17

(b) SOYD method

Sum-of-years-digit (SOYD) = 1 + 2 + 3 + 4 + 5 + 6 = 21

Annual depreciation in year N = (Cost - Salvage Value) x (Number of years remaining at beginning of year N / SOYD)

= (4,000 - 1,000) x (Number of years remaining at beginning of year N / 21)

= 3,000 x (Number of years remaining at beginning of year N / 21)

SOYD Depreciation schedule for 4 years as follows.

SOYD
Year Cost Basis ($) Depreciation Rate Annual Depreciation ($) Accumulated Depreciation ($) End-of-Year Book Value ($)
1 3,000 6/21 857.14 857.14 2,142.86
2 3,000 5/21 714.29 1,571.43 1,428.57
3 3,000 4/21 571.43 2,142.86 857.14
4 3,000 3/21 428.57 2,571.43 428.57

(c) SLM method

SL annual depreciation = (Cost - Salvage value) / Useful life = (4,000 - 1,000) / 6 = 3,000 / 6 = 500

SLM accumulated depreciation in 2 years = 500 x 2 = 1,000

Book value after 2 years = Cost - SLM accumulated depreciation in 2 years = 3,000 - 1,000 = 2,000

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