What is the equilibrium expression for the following system? B2O3(s) + 6HF(g) ↔ 2BF3(g) + 3H2O(g)...

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What is the equilibrium expression for the following system? B2O3(s) + 6HF(g) ↔ 2BF3(g) + 3H2O(g)...

What is the equilibrium expression for the following system? B2O3(s) + 6HF(g) ↔ 2BF3(g) + 3H2O(g)

Question 2 options: a) Kc = [BF3]2 [H2O] / [HF]6 b) Kc = [BF3]2 [H2O]3 / [B2O3][HF]6 c) Kc = [B2O3][HF]6 / [H2O]3 [BO3]2 d) Kc = [BF3]2 [H2O]3 / [HF]6 e) Kc = [BF3]2 [H2O]3 / [HF]

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Answer 1

Answer #1

Kc is defined as concentration of product by concentration of reactant with each concentration term raised to power that is equal to its stoichiometric coefficient in balanced equation
pure liquid and solid do not appear in Kc
So, B2O3(s) will not appear in Kc expression.

So,
Kc = [BF3]^2[H2O]^3 / [HF]^6

Answer: d

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Answer 2

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