Question

6. Calculate the rate constant kı2 for the below outer-sphere electron transfer reaction: [Fe(CN)6]4-+ Cet+ → [Fe(CN)6]>- + Ce 3+ E' = 0.76 V, T = 300 K, log f= -2.33 The relevant self-exchange rate constants are: [Fe(CN)6]4-13 kui = 7.4 x 102 M-- k22 = 4.4 M-3-1 Ce4+/3+

Answer 1

1 - The Given neaction is - [Feccardo)" + cert [reccano y acest the above reaction ý given The date constant for by K12= Kil Kez. Kof whene Kila K2 ane self-exchange date constant Af evilibrium G C 0-0591 poglk) =0 7 Eºs 0.059, logiky (1 In Huis cose, n=1) → 0.76 = 0.0591 logik) - K= 7.23x1012 Also given logfs -2.33; f= 0.00467 she nate constant for the given outed-sphene election transben reaction K12= 7.4x10²x u.4 x 7 23x102x 0.00467 El.ogx 1044