W = {a,b,c,d,e,f,g}
R is WxW
Given, R =
(a,b),(a,c),(a,f),(b,c),(b,f),(c,f),(d,a),(d,b),(d,c),(d,e),(d,f),(d,g),(e,a),(e,b),(e,c),(e,f),(f,c),(g,a),(g,b),(g,c),(g,e),(g,f)
a. Let us denote the relations using for preference
and for
indifference.
a | b | c | d | e | f | g | |
a | |||||||
b | |||||||
c | |||||||
d | |||||||
e | |||||||
f | |||||||
g |
In the table, the rows represent the first element of the
relation, and the columns represent the second element.
b. Now, using the table we made above, we try to find the
preference order, listing it in a column.
D is preferred over every other element, making it first. After D,
G is preferred, so it occupies second place. After these two, E
comes third. After E, A is the fourth alternative. Following A is B
as the fifth alternative. C and F are equally preferred, at last,
so we place them together.
D |
G |
E |
A |
B |
C,F |
c. Now we represent R by means of a utility function, where
negative integers are chosen as utility numbers.
The utility function u : X -> R represents the binary
relation on X if x
y means that u(x)
> u(y).
Since we've been told to use negative integers, let us create a
formula to assign numbers. Let u(x) be such that it counts the
number of elements preferred to x (with a negative sign).
So, for instance, with d, u(d) = 0, but since we want negative
integers, we subtract 1. Thus, u(d) = -1.
u(g) = 1. We put a negative sign here and subtract 1. Thus, u(g) =
-2.
Since d g, u(d) > u(g)
-> this relation checks out.
Next, u(e) = -3
u(a) = -4
u(b) = -5
And since c and f are equally preferred, they will have the same
utility number. This number will be the lowest since they are least
preferred.
u(c) = u(f) = -6
Hope this helped!
3. Consider the following set of alternatives W - la,b,c,d,e.f.g) and the following complete and transitive...