I titrated sodium carbonate in a commercial soda sample with a strong acid, HCl, and it gave me two equivalence points in a titration curve graph. What do these two equivalence points mean?
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I titrated sodium carbonate in a commercial soda sample with a
strong acid, HCl, and it...
Given that the pKa for the half equivalence point is = 5.5, and the pKa of...
Given that the pKa for the half equivalence point is =
5.5, and the pKa of Acetic acid is 4.76, what is the percent
error?
Is 4.76 the accepted value?
and 5.5 the experimental?
and so...
|4.76-5.5| = -0.74
--------- ----- = 0.15546 ×100% = 15.55%
|4.76|
|4.76|
Please verify I am correct.
Vinegar Titration Curve / / 14.00 13.00 12.00 11.00 10.00 9.00 8.00 E 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 5.00 10.00 25.00 30.00...
which is correct? please explain Identify the predominant reaction taking place in the solution at point...
which is correct? please explain
Identify the predominant reaction taking place in the solution at point A, 0 mL NaOH added. Acetic Acid Titration Curve 14.00 13.00 12.00 11.00 10.00 9.00 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 25.00 30.00 35.00 5.00 10.00 15.00 20.00 Volume NaOH (mL) HC2H302(aq) + OH - (aq)=C2H302-(aq) + H2O(1) HC2H302(aq) + H20(1) = C2H302 (aq) + H30+(aq) o C2H302 (aq) + H2O(1) = HC2H302(aq) + OH- (aq)
Laboratory Report CHM-153 General Chemisiry Principles il DATE NAME IONIZATION CONSTANT OF A WEAK ACID Trial...
Laboratory Report CHM-153 General Chemisiry Principles il DATE NAME IONIZATION CONSTANT OF A WEAK ACID Trial A Trial B Vol. NaOH to reach equivalence point (ML): Vol. NaOH to reach half-equivalence pt. (mL): -_ pH at half-equivalence pt. (pka): Include your calculations showing how you derived pKfrom K *Remember to include your data sheet and Excel plots (titration plots and first derivative plots). IONIZATION CONSTANT OF A WEAK ACID pH (Trial B, optional) Volume NaOH (mL) 0.00 5.00 10.00 15.00...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 pH 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
Refer to the data set (four years of ratios and graphs) in the Saputo vs Maple...
Refer to the data set (four years of ratios and graphs) in the
Saputo vs Maple Leaf Foods to perform trend, cross-sectional, and
integrative analysis.
start by providing your recommendation – to
invest in Saputo or to invest in Maple Leaf foods.
Return on equity 20.00% 15.00% Gross profit percentage 35.00% 30.004 25.000 20.004 15.00 10.000 5.00% Saputo Maple Saputa Maple 10.00% 5.00% 0.0006 0.004 2015 2016 2017 2018 2015 2016 2017 2018 Inventory turnover ratio Net profit margin percentage...
Following the Procedure of this experiment, a student titrated 0.653 g of an unknown weak, monoprotic...
Following the Procedure of this experiment, a student titrated 0.653 g of an unknown weak, monoprotic acid with 0.100 M NaOH and monitored the titration with a pH meter. His titration data were: Volume of NaOH solution added, mL /// pH 0.00 | 3.30 2.00 | 4.22 4.00 | 4.55 6.00 | 4.76 8.00 | 4.92 10.00 | 5.06 12.00 | 5.18 14.00 | 5.29 16.00 | 5.40 18.00 | 5.51 20.00 | 5.62 22.00 | 5.74 24.00 | 5.88...
284 Report Sheet . Determination of the Dissociation Constant of a Weak Acid 2.96 2.99 4.37...
284 Report Sheet . Determination of the Dissociation Constant of a Weak Acid 2.96 2.99 4.37 4.55 C. Determination of pKof Unknown Acid First determination Second determination ml NaOH pH ml NaOH pH 0.00 mL 0.00 mL 1.00 mL 2.00 mL 2.00 mL 4.00 mL 3.64 3.00 mL 6.00 ml 3.97 4.00 mL 7.00 ml 4.17 5.00 ml 8.00 mL 6.00 mL 9.00 ml. 7.00 mL 9.50 mL 4.61 8.00 ml 10.00 ml 4.71 9.00 mL 10.50 ml 4.85 10.00...
Given that the pKa for the half equivalence point is =
5.5, and the pKa of Acetic acid is 4.76, what is the percent
error?
Is 4.76 the accepted value?
and 5.5 the experimental?
and so...
|4.76-5.5| = -0.74
--------- ----- = 0.15546 ×100% = 15.55%
|4.76|
|4.76|
Please verify I am correct.
Vinegar Titration Curve / / 14.00 13.00 12.00 11.00 10.00 9.00 8.00 E 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 5.00 10.00 25.00 30.00...
which is correct? please explain
Identify the predominant reaction taking place in the solution at point A, 0 mL NaOH added. Acetic Acid Titration Curve 14.00 13.00 12.00 11.00 10.00 9.00 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 0.00 25.00 30.00 35.00 5.00 10.00 15.00 20.00 Volume NaOH (mL) HC2H302(aq) + OH - (aq)=C2H302-(aq) + H2O(1) HC2H302(aq) + H20(1) = C2H302 (aq) + H30+(aq) o C2H302 (aq) + H2O(1) = HC2H302(aq) + OH- (aq)
Laboratory Report CHM-153 General Chemisiry Principles il DATE NAME IONIZATION CONSTANT OF A WEAK ACID Trial A Trial B Vol. NaOH to reach equivalence point (ML): Vol. NaOH to reach half-equivalence pt. (mL): -_ pH at half-equivalence pt. (pka): Include your calculations showing how you derived pKfrom K *Remember to include your data sheet and Excel plots (titration plots and first derivative plots). IONIZATION CONSTANT OF A WEAK ACID pH (Trial B, optional) Volume NaOH (mL) 0.00 5.00 10.00 15.00...
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 pH 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
1. The following graph is provided for the titration of 10.00 mL benzoic acid solution with a strong base. The concentration of NaOH is 0.100 M. A. Based on this graph given below, determine the Ka. B. Determine the molarity of the acid. Benzoic acid titration with 0.1 M NaOH 12.00 10.00 8.00 6.00 4.00 2.00 0.00 0.00 5.00 10.00 15.00 Volume of NaOH mL
Refer to the data set (four years of ratios and graphs) in the
Saputo vs Maple Leaf Foods to perform trend, cross-sectional, and
integrative analysis.
start by providing your recommendation – to
invest in Saputo or to invest in Maple Leaf foods.
Return on equity 20.00% 15.00% Gross profit percentage 35.00% 30.004 25.000 20.004 15.00 10.000 5.00% Saputo Maple Saputa Maple 10.00% 5.00% 0.0006 0.004 2015 2016 2017 2018 2015 2016 2017 2018 Inventory turnover ratio Net profit margin percentage...
284 Report Sheet . Determination of the Dissociation Constant of a Weak Acid 2.96 2.99 4.37 4.55 C. Determination of pKof Unknown Acid First determination Second determination ml NaOH pH ml NaOH pH 0.00 mL 0.00 mL 1.00 mL 2.00 mL 2.00 mL 4.00 mL 3.64 3.00 mL 6.00 ml 3.97 4.00 mL 7.00 ml 4.17 5.00 ml 8.00 mL 6.00 mL 9.00 ml. 7.00 mL 9.50 mL 4.61 8.00 ml 10.00 ml 4.71 9.00 mL 10.50 ml 4.85 10.00...
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