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3 If Derek plans to deposit $10,558.00 into his retirement account on each birthday beginning with his 26th and the account e
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Answer 3 : In question number 3 take the assumption for 30 years and calculate the accumulated amount in the following manner:

Year Compounded Interest rate Accumulated Amount
30 (1.11)30 =22.89 22.89*10558 = 241672.62
29 (1.11)29 =20.62 20.62*10558 = 217705.96
28 (1.11)28 =18.58 18.58*10558 = 196167.64
27 (1.11)27 = 16.74 16.74*10558 = 176740.92
26 (1.11)26 = 15.08 15.08*10558 = 159214.64
25 (1.11)25 = 13.59 13.59*10558 = 143,483.22
24 (1.11)24 = 12.24 12.24*10558 = 129,229.92
23 (1.11)23 = 11.03 11.03*10558 = 116,454.74
22 (1.11)22 = 9.93 9.93*10558 = 104,840.94
21 (1.11)21 = 8.95 8.95*10558 = 94,494.10
20 (1.11)20 = 8.06 8.06*10558 = 85,097.48
19 (1.11)19 = 7.26 7.26*10558 = 76,651.08
18 (1.11)18 = 6.54 6.54*10558 = 69,049.32
17 (1.11)17 = 5.90 5.90*10558 = 62,292.20
16 (1.11)16 = 5.31 5.31*10558 =56,062.98
15 (1.11)15 = 4.78 4.78*10558 = 50,467.24
14 (1.11)14 = 4.31 4.31*10558 = 45,504.98
13 (1.11)13 = 3.88 3.88*10558 = 40,965.04
12 (1.11)12 = 3.50 3.50*10558 = 36,953.00
11 (1.11)11  = 3.15 3.15*10558 = 33,257.70
10 (1.11)10 = 2.84 2.84*10558 =29,984.72
09 (1.11)9  = 2.56 2.56*10558 = 27,028.48
08 (1.11)8 = 2.30 2.30*10558 = 24,283.40
07 (1.11)7 = 2.08 2.08*10558 = 21,960.64
06 (1.11)6 = 1.87 1.87*10558 = 19,743.46
05 (1.11)5 = 1.69 1.69*10558 = 17,843.02
04 (1.11)4 = 1.52 1.52*10558 = 16,048.16
03 (1.11)3 = 1.37 1.37*10558 = 14,464.46
02 (1.11)2 = 1.23 1.23*10558 = 12,986.34
01 (1.11)1  = 1.11 1.11*10558 = 11,719.38

Total accumulated balance after 30 years of investment at the end of 30th year will be 2,332,357.78.

At the end of 31st year the amount will be :

(2,332,357.78*1.11) + (10,558*1.11) = 2,588,917.14 + 11,719.38 = 2,600,636.52

At the end of 32nd year the amount will be :

(2,600,636.52*1.11) + (10,558*1.11) = 2,886,706.54 + 11,719.38 = 2,898.425.92

So the accumulated amount which is required is $2,814,980.00 and the amount at the end of 32nd year is more than the required accumulated balance which means that we do not have to invest the amount for the whole 32nd year.

So the time period for which the amount should be invested is in between 32 years and 33 years.

So the amount which will be invested at the beginning of the 32nd year will be $2,600,636.52 + $10,558 = $2,611,194.52. The amount of interest for the 32nd year will be $203,785.48 i.e. $2,814,980 - $2,611,194.52.

Period for such interest will be calculated as below:

2,611,194.52 * 11% * No. of months/12 = 203,785.48

No.of months * 23935.95 = 203,785.48

No. of months = 203,785.48/23,935.95

No. of months = 8.51

So the total time period will be 31 years and 8.51 months or 31.71 years (approximately)

Question 4 . To answer this question we have to do the reverse calculation to arrive at the principle amount:

like to arrive at the value of $198,343.00 on his 86th birthday we have to use the following formula:

Present value divided by (1.05)n. Here n represent the number of year form his 65th birthday. So on 86th Birthday the value of n will be 21.

Years Accumulated interest rate Accumulated Amount required Value of amount of 65th Birthday = Column3/Column2
21 (1.05)21 = 2.79 198,343 71,090.68
20 (1.05)20 = 2.65 198,343 74,846.42
19 (1.05)19 = 2.53 198,343 78,396.44
18 (1.05)18 = 2.41 198,343 82,300.00
17 (1.05)17 = 2.29 198,343 86,612.66
16 (1.05)16 = 2.18 198,343 90,983.03
15 (1.05)15 = 2.08 198,343 95,357.21
14 (1.05)14 = 1.98 198,343 100,173.23
13 (1.05)13 = 1.89 198,343 104,943.39
12 (1.05)12 = 1.80 198,343 110,190.56
11 (1.05)11 = 1.71 198,343 115,990.06
10 (1.05)10 = 1.63 198,343 121,682.82
09 (1.05)9 = 1.55 198,343 127,963.23
08 (1.05)8 = 1.48 198,343 134,015.54
07 (1.05)7 = 1.41 198,343 140,668.79
06 (1.05)6 = 1.34 198,343 148,017.16
05 (1.05)5 = 1.28 198,343 154,955.47
04 (1.05)4 = 1.22 198,343 162,576.23
03 (1.05)3 = 1.16 198,343 170,985.34
02 (1.05)2 = 1.10 198,343 180.311.82
01 (1.05)1 = 1.05 198,343 188,898.10

Total amount to be available on the 65th Birthday will be $  2,540,958.18

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