Question

Part E 4.78x104 kJ/mol IVO ALQ * 0 2 ? Submit Request Answer Part F o visible light O infrared O microwave O X ray Submit Request Answer

Answer 1

Part E. Energy is given as 4.78 × 10" kJ/mol. This is the energy of mole of particles and mole of any sulostance contains Avogadro's Nuhber, that is 6.022 x 1023 particles... Thus Energy of Imole of particles is 4.78 X104 por 4:78 x Paxles I because I kila (&) = 103 units -_Thures &j siost a

Energy $ 6.022.X102 particles - 4:78x109 xlo't - 24.78x10? I Energy of single particle - 4.78 x 10 g 6:022 x1013 34.78X18"-29 6.022 30.7938.x1016 J ( The sign of exponent reverses on going from denominator to numerator and vice versa sot = 10-23 . _ 1023. Also when base is same powers are added. so 10²x10-23 = 107+(-23) = 107-23) Now Energy is related to wavelength by the relation : E = he à ' where h is Planck's constant, - c is velocity of light and s is the wavelength from ④ we can calculate wavelength as x = he > Planck's constant (a) = 6.626 X 10-34 Js. Velocity of light (c) = 3 x 108 m/s Energy thy = 0:79.38X10515 J

using these values in ③ we get ____ : (6.626 1034 ) (3x to ans) 1-/\६४१८१.97 - (0 ऽर) : (+3+ne -> = 25.०.५ x 10°m

Part of Since wavelength (x) = 25.04x100 m . or 2.504 x 10-9 m 2.soy un L (Because Inano (n) = 10-9 units so Inm = 1000m) 1 -
The range of wavelengths of the different regions of the electromagnetic spectrum are :

Region of electromagnetic spectrum	Wavelength (nm)
Gamma rays	less than 1
X-rays	1-10
Ultraviolet rays	10-400
Visible light	400-700
Infrared	700-105
Microwaves	105-108
Radio waves	more than 108

Since this wavelength is of 2.5 nm so it belongs to the range 1-10 nm which belongs to the region of X-rays.

Thus answer to part F is X-ray.