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11) A pump has an initial cost of $20,000 and an annual maintenance cost of $550. The life of the pump is 15 years, and its s
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c.$2120.

first let us know the present value of annual maintenance cost.

=>$550 * PV of annuity factor for 15 years @4%.

PV of annuity factor = [1-(1+r)^(-n)]/r

here,

r= 4%=>0.04.

n=15.

PV of annuity factor = [1- (1.04)^(-15)]/0.04

=>0.4447355/0.04

=>11.1183875.

now,

present value of annual maintenance costs =550*11.1183875

=>6,115.11.

now present value of salvage value

=>$4500*1 / (1.04)^15

=>2498.69.

now,

present value of pump = 20,000+6115.11-2498.69

=>26,616.42.

equivalent uniform annual cost = $26,616.42 /PV of annuity factor for 15 years @4%.....(as calculated above)

=>26,616.42/11.1183875

=>$2,124.

nearest to 2120.

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