c.$2120.
first let us know the present value of annual maintenance cost.
=>$550 * PV of annuity factor for 15 years @4%.
PV of annuity factor = [1-(1+r)^(-n)]/r
here,
r= 4%=>0.04.
n=15.
PV of annuity factor = [1- (1.04)^(-15)]/0.04
=>0.4447355/0.04
=>11.1183875.
now,
present value of annual maintenance costs =550*11.1183875
=>6,115.11.
now present value of salvage value
=>$4500*1 / (1.04)^15
=>2498.69.
now,
present value of pump = 20,000+6115.11-2498.69
=>26,616.42.
equivalent uniform annual cost = $26,616.42 /PV of annuity factor for 15 years @4%.....(as calculated above)
=>26,616.42/11.1183875
=>$2,124.
nearest to 2120.
show your work 11) A pump has an initial cost of $20,000 and an annual maintenance...
1. A new pipeline is installed. Annual maintenance and pumping costs are considered to be paid in their entireties at the end of the years in which their costs are incurred (assume that maintenance happens in year 10). The pipe has the following costs and properties: Initial cost $7,500 Annual interest rate 5% Service life 10 years Salvage value $500 Annual maintenance $500 Pump cost/hour $2.75 Pump operation 2000 hours/year What is the equivalent uniform annual cost (EUAC) of the pipe?
PROBLEM NO. 4 Machine X has an initial cost of $10,000, annual maintenance of $500 per year, and no salvage value at the end of its four-year useful life. Machine Y costs $20,000. The first year there is no maintenance cost. The second year, maintenance is $100, and increases $100 per year in subsequent years. The machine has an anticipated $5,000 salvage value at the end of its 12-year useful life. If interest is 8%, which machine should be selected?...
A municipal council purchased a water supply pump at a cost of RM 200,000 two years ago to be useful for eight years. This pump can be replaced with an improved version for preference and satisfaction of public water supply in municipal area. The present market value, annual maintenance cost and ultimate salvage value of the two pumps are given in Table 4. The expected economic life of the improved version pump is six years. The bank interest rate is...
answer all questions please 15. A company is considering buying a computer with the following costs and interest rate. initial cost $3900 salvage value $1800 useful life 10 years annual maintenance $390 interest rate 69 Most nearly, what is the equivalent uniform annual cost (EUAC) of the computer? (A) $740 (B) $780 (C) $820 (D) $850 20. An engineer is evaluating two options for distribut- ing products from a production facility: renting or own ing trucks. The effective annual interest...
Two pumps are being considered for purchase. Pump A has an initial cost of $7,000; a useful life of 12 years and a salvage value of $1,200 at the end of its life. Pump B has an initial cost of $5,000; a useful life of 6 years and a salvage value of $1,000 at the end of its life. Using EUAC and a 7% interest, which pump should be chosen. No answer text provided. Pump B Correct! O Pump A...
Find the equivalent uniform annual cost 3. Using an interest rate of 12%, find the equivalent miform annual cost for a piece of construction equipment that has an initial purchase cost o $30,000, an estiinat nomic life of 8 years, and an estimated salvage value of $10,000. Annual mainte- nance will anount to $600 per year and periodic overhauls costing $1.,000 each will occur at the end of the second, fourth, and sixth years. 3. Using an interest rate of...
show your work 10) An oil company is planning to install a new pipeline to connect storage tanks to a processing plant 1500 m away. A 120 mm pipe is being considered with the following characteristics. What is the benefit-cost ratio for this pipe using an annual interest rate of 10%? Initial cost $2500 Service Life 12 Years Salvage Value $300 Annual Maintenance $300 Pump Cost/Hour $1.40 Pump Operation 600 hours/year Estimated Benefits $2000/year a. 1.22 b. 1.34 c. 1.45...
7. A tower crane has the following costs, and can be sold to a salvage yard at the end of its useful life of 12 years. What are the maintenance costs in year six? What is the equivalent uniform annual cost (EUA%) of the crane using an annual interest rate of 10%? Initial cost Annual operating costs Annual maintenance costs Salvage value F 140,000 20,000 15,000 at the end of year 12 $ 10,000 in year 1, increasing by 10%...
Machine X has an initial cost of $14,000. It is expected to last 10 years, to cost $255 per year to maintain and to have a salvage value of $6,000 at the end of its useful life. The equivalent uniform annual cost of the machine at 7% interest is approximately _____________.
Please show code if you use excel thank you. Project A has a first cost of $3,500, annual operating and maintenance costs of $1,900, annual savings of $2,300, and a salvage value of $1,800 at the end of its 5 year useful life. Project B has a first cost of $6,000, annual operating and maintenance costs of $1,600, annual savings of $2,500, and a salvage value of $2,000 at the end of its 7 year useful life. Using a MARR...