Question

() Calculate the magnitude (in N) and direction of the force (in degrees counterclockwise from the vertical) on each foot of the horse in figure (b) (two are on the ground), assuming the center of mass of the horse is midway between the feet. The total mass of the horse and rider is 524 kg 1.0 m 1.4 m 0.36 m (a) (b) magnitude Counterclockwise from the vertical direction (b) What is the minimum coefficient of friction between the hooves and ground? Note that the force exerted by the wall is horizontal.

Answer 1

Soluhan Det fance om each foot - f Nit F.B.D of hanse: falt 1.om 0:36 & fy2O => fy-w =0 fy - W=524 x 9.8 = 5135-2 N ET 20 about paint p - Fwall & Lot w x 0.36=0 fwall = 5135,2 X 0.36 fwall = 1848.672 M How Efnzo fut fwall =0 fu = - wall = - 1848.672 M 1848-6721 5135-2 N 135.2)2 +0848.672)2 F = 5457.83 M tan c = 1848.672 5135:2 0 = 19.799 Now fe total force on two foot .: fance an- each foot - 5457.83 2728.915 N 0 = 19.7999 c4 - fwall - ma 1898.672 - 50-36 524 x 9-8 Ma 0036 :: Coefficient of frichiam = 0.36

Please rate
if any mistake in this answer please comment i will clarify your doubt . thank you