How do I solve this? When the temperature of 2.35 mA3 of a liquid is increased...

Question

Question

How do I solve this?

Answer 1

Answer #1

Solution) Vo = 2.35m^3

dV = 0.0920m^3

dT = 48.5°C

We have

dV = (coefficient of volume expansion)(Vo)(dT)

Coefficient of volume expansion = (dV)/(VodT)

Coefficient of volume expansion = (0.0920)/(2.35×48.5)=8.07×10^(-4) C^(-1)

Answer 2

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