induviduals who have a particular gene have a .72 probability of contracting a certain disease suppose that 526 induviduals with the gene participate in a lifetime study what is the standard deviation of the number of people who eventually contract the disease?
SOLUTION:
Given that,
p = 0.72
q = 1 - p =1-0.72=0.28
n = 526
Using binomial distribution,
= n * p = 526*0.72=378.72
STANDARD DEVIATION = n * p * q = 526*0.72*0.28=10.2976
induviduals who have a particular gene have a .72 probability of contracting a certain disease suppose...
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