Question

1) If a particular utility burned 1.70 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide was emitted?
2) A coal-burning power plant generates 5.5 ×10¹⁶ J per year. If the coal yields 37 kJ/g, how many grams of coal was burned each year?

Answer 1

Page No.: 1 ton = 1000kg from 1 kg = 1000g = 1000 x 1000 g = 1033 10 g 1.7 million ton = 1.78106 ton XO Total coal = 1.7x10 ton = 1.7x 106 x 100 g 2 1.7 x 10.2 g Sulphus weight = 2.1. Sulfur weight a 2% x 1.7x102 - 2x 1•7X1012 3:4X100g 100 100 Moles of moles - Weight - 34 x 100 g. Molero Mass = 1.0625x10?mole St O SO Imole of sulfur yields 1 mole of so 1006 25 x 109 mole of sulfur will yield. = 1.0625X 10'mol of soz Mass of sulfur dioxide formed = Moles Molar Mass = .0625x109mol XG4gland = 68x109 mong Convest grams back to tons. Mass of SO2 = 68x1099 = 68X10% tons

Power requirement=5.5x1016 J coal yields = 37 kJ/g = 37x10 3 5/8 Mass of coal needed - 5.5x 126 I ot doix Fer = 37x10351g - 1o49 x 10.2 g 1049x102 grams of coal burned each year