Question

1.) Use the ideal gas law to calculate the volume occupied by 0.500 mol of nitrogen gas at 1.60 atm pressure and at 27°C. R = 0.0821 L_*atm/(K^_*mol).

0.694 L

7.10 L

7.70 L

7.89 L

(separate question)

2.What will be the final gas temperature in kelvins?

Answer 1

w gas equation PV = nRT n = 0.500 mol R = 0.0821 V = nRT atm. L mol-k P = 1.60 atm V = (0.500 mol ) (0-082) adm.l )« (300k) molok T = 27° c = 273 +27k = 300k 1.60 atm v= 7.69 L V= 7.70 L