Question

6) In both [Fe(H20).]** and [Fe(CN)61* ions, the iron is present as Fe(11); however, [Fe(H20)6]** is paramagnetic, whereas [Fe(CN)6] is diamagnetic. Please write the electronic configuration of d-orbital for these two complexes and explain this difference. (8 marks) Fe2+ = 15² 25² 2p% 35² 306 45 306 act 6 = -a 30-446

Answer 1

B MAMA20242428042A002919 S dws) Enc of fe= [Ar] 3h 8 45² Solution O [Fe (120)]" in this complex state of fe di Pezt B so. GoC of Fe2t - [Ar] 3 d feat 1117110 H₂O is weak régend So, lit fauld to hair-election. 45 4P 11 10 TIL varlar C rearrangement ho 10 ho ho SP3 3 0 unpaired é = 4² So this pava magnette .. 3 © Petatlists [Fe(CN),J" in this complex utete = 80. E. C of feat = [Ar] 3 do of fe is in feet 99999

CN is stronge field Egent, So. paising of e- occour en us UP AV AV 9V 12V Receweagement Ocecome due to feild of CN ligent. infaised to the fore= 0 Diamgnetic Explaination • so as you can see, No of no of Unhaired 6) is o so it is diamgnetic and no of unpaired e in [Fe (H2O),]ht is 4 Ao it is peramagnetic Thank you, May dit help you...