Question

Review Toples) References) Use the References to important values if reded for this question For the following reaction, 20.1 grams of iron are allowed to react with 42.9 grams of chlorine gas iron (s) + chlorine() iron(III) chloride (s) What is the maximum amount of iron(III) chloride that can be formed? What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is co Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

Mass so feelz - soles & Molar mass = 0.359 X (62 - 58. 158 g = 58. 29 The limiting regent is re. - Te no. de moles so excess ch = 0.bolu – 0.539 is (present - required) 0.065 moles. Mass of cle exces & molej & = 0.065 & nolar mass 7 - u. 629

a Fe + scha – 2 feel, This is the balanced equation. mass of Iron - 20:19 It moles – mass molar mass 20.1 - 56 = 0.359 moles. Mass os chlorine = 42.9 g Its moles - mass molar mass - = 0.6o4 modes. U2.9 = 2 moles of Fe - needs & moles of cle 0.359 molas sofe needs a moles de ce = 0.359x2 = 0.539 ndes. But thech is an leigher number. so, the product is Calculated according to produces, a moles of 2 moles of. Fe feel, moles it feel, formed - 0-359 moles.