Question

A 0.557 g sample of cobalt, Co, is added to 206 mL of 0.100 MH,SO, to produce cobalt(II) sulfate and hydrogen gas. Co(s) + H2SO4(aq) — Coso, (aq) + H2(g) What is the limiting reactant? OH,SO4(aq) Co(s) A volume of 139 mL of hydrogen is collected over water. The water level in the collecting vessel is the same as the outside level. Atmospheric pressure is 101.325 kPa, the temperature is 25 °C, and the vapor pressure of water at 25 °C is 3.167 kPa. What is the percent yield of hydrogen gas for this reaction? percent yield:

Answer 1

vowme V 139m of H₂ = 139 ml x 0.0012 0.1292 - 1 ml TEMPERMURE, T: 25+ 273 = 298 K. NO. OF moles of H₂ , n= pure n=0.969 alm x 0.139L 0.08206 I alm x 298 € No. of moles of Cogner: Mass of COBALT AT WT. OF LOBALT = 0.5979 58.933gmoet = 9,45 x10 mot NO- of moles Of 4,804 : 0.100 mpl x 206 ml * 0.001L Ime - = 0.0206 mol Асоёо 15 т В и еq . o two H, Кема IN lil molt RAMO. But Co is in LESSER Amount: LIMITING REAGENT: Co (6) : Prome = PH₂O + PH2 101.325 kPa - 3.167 kPa + Pitan Paariae PRESSURE op Hy = 880158 kPa = 98.158 kpa x 9.87 x10 alim 1 kpa n= 5.81 x 103 moe (Acture) I mue Co 4iElbe 1 mol H₂ So 9.45 x103 mor to VIELD 9.45x10 moe He: 9.45* 10 moe YIELD = THEORETICAL PERCENT YIElo= ACTUAL YIELD 100 THEORETI are hicho 5.51 x10 ml x 100 9.45x10 moe 58.3 % 17 = 0.969 alin