What volume (in L) of a 4.57 M NaOH solution is required to titrate 5.87 mol H2SO4 ?
Give your answer to 3 sig figs.
H2SO4(aq) + 2 NaOH(aq) → Na2SO4(aq) + 2 H2O(l)
Balanced chemical equation is:
2 NaOH + H2SO4 ---> Na2SO4 + 2 H2O
Mol of NaOH reacting = 2*mol of H2SO4
= 2*5.87 mol
= 11.74 mol
Now use:
Mol of NaOH = M(NaOH)*V(NaOH)
11.74 mol = 4.57 M * V(NaOH)
V(NaOH) = 2.57 L
Answer: 2.57 L
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