Homework Answers
a)
If one person is selected randomly,
Probability of getting someone who is type Rh- = Number of persons who is type Rh- / Total number of persons = 24/120 = 0.2
b)
If one person is selected randomly,
Probability of getting someone who is not Group A = 1- Probability of getting someone who is Group A
Probability of getting someone who is Group A= Number of persons who is Group A / Total number of persons = 50/120
Probability of getting someone who is not Group A = 1- Probability of getting someone who is Group A = 1 -50/120 = 70/120=0.5833
c)
If one person is selected randomly, Probability of getting some person who is group A or group B
A : Event of person who is group A
B : Event of person who is group B
If a person is Group A , he can not be group B i.e A and B is null
Therefore, P(A or B) = P(A) + P(B)
P(A) = Probability of getting someone who is Group A = 50/120
P(B) = Probability of getting someone who is Group B =Number of persons who is Group B / Total number of persons = 20/120
P(A or B) = P(A) + P(B) = 50/120 + 20/120 = 70/120=0.5833
If one person is selected randomly, Probability of getting someone who is group A or group B = 70/120=0.5833
d)
If one person is selected randomly, Probability of getting someone who is group A or type Rh-
A : Event of person who is group A
Rh- : Event of person who is type Rh-
Therefore, P(A or Rh-) = P(A) + P(Rh-) +P(A and Rh-)
P(A) = Probability of getting someone who is Group A = 50/120
P(Rh-) = Probability of getting someone who is type Rh- =Number of persons who type Rh- / Total number of persons = 24/120
P(A and Rh-) = Probability of getting someone who is group A and type Rh- = Number of persons who is Group A and type Rh- / Total number of persons = 15/120
P(A or Rh-) = P(A) + P(Rh-) -P(A and Rh-) = 50/120 + 24/120 -15/120 = 59/120=0.491666667
If one person is selected randomly, Probability of getting someone who is group A or type Rh- =59/120=0.4917
e)
If three people are selected randomly(with replacement), Probability of finding three that have group B
P(B) = If one person is selected randomly, Probability of getting someone who is group B = Number of persons who is group B /Number persons = 20/120
If three people are selected randomly(with replacement), Probability of finding three that have group B
= P(B)P(B)P(B) = (20/120)(20/120)(20/120) = 0.00462963
If three people are selected randomly(with replacement), Probability of finding three that have group B = 0.00462963
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