Question

osisive diection. Refer to the

Answer 1

From given data v1=65mile/hr

v2=31mile/hr

d=.15mile

In order to just avoid collision the velocity of both cars must be same.

Let after (t) car reaches the truck

Using s=ut+1/2at^2

For truck

s=31t.............1

For car

s+.15=65t-0.5at^2...............2

subtracting 2 equation.

0.15=34t-.5at^2.............3

Also equating velocities at t

31=65-at

at=34.....4

Substituting in 3

0.15=34t-.5*34*t

17t=.15

t=31.76s

substituting in 4

a=1.07mile/s^2