given
Y_hair = 3.80*10^9 N/m^2
d = 150 micro m
r = d/2 = 75 micro m
L = 15 cm = 0.15 m
m = 234 g
= 0.234 kg
a) use, Y = (F/A)/(delta_L/L)
delt_L/L = F/(A*Y)
delta_L = L*F/(A*Y)
= L*m*g/(A*Y)
= 0.15*0.234*9.8/(pi*(75*10^-6)^2*3.8*10^9)
= 5.12*10^-3 m <<<<<<<------------------------------Answer
b) for aluminimum, Y = 68.9*10^9 N/m^2
delta_L_al = L*m*g/(A*Y)
= 0.15*0.234*9.8/(pi*(75*10^-6)^2*68.9*10^9)
= 2.83*10^-4 m <<<<<<<------------------------------Answer
c) k_hair = m*g/delta_L
= 0.234*9.8/(5.12*10^-3)
= 448 N/m <<<<<<<------------------------------Answer
A particular human hair has a Young's modulus of 3.80 x 10 N/m² and a diameter...
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