Given,
q = -344 e ; r = 4.8 cm ; theta = 59
q = -344 x 1.6 x 10^-19 = -5.5 x 10^-17 C
lambda = q/L
L = r theta(radians)
L = 4.8 x 1.03 = 4.94 cm
lambda = -5.5 x 10^-17/0.0494 m = -1.11 x 10^-15
Hence, lambda = -1.11 x 10^-15 C/m
b)r = 4.5 cm
sigma = Q/A = Q/pi r^2
sigma = -5.5 x 10^-17/(3.14 x 0.045^2) = -8.65 x 10^-15 C/m^2
Hence, sigma = -8.65 x 10^-15 C/m^2
c)r = 3.1 cm
sigma = Q/V = Q/4 pi r^2
sigma = -5.5 x 10^-17/(4 x 3.14 x 0.031^2) = -4.56 x 10^-15 C/m^2
Hence, sigma = -4.56 x 10^-15 C/m^2
d)r = 3.2 cm
rho = Q/V = Q/(4/3 pi r^3)
rho = -5.5 x 10^-17/(4/3 x 3.14 x 0.02^3) = -1.64 x 10^-12 C/m^3
Hence, rho = -1.64 x 10^-12 C/m^3
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