Question


The synthesis of an ester by the reaction of a carboxylic with an alcohol is an equilibrium reaction. H - R-OH HO ROH R OR, R

acetic acid is 25 ml and alcohol is 20 ml
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Answer #1

Ans 1:

During the esterification procedure water will be removed as soon as it is formed. This shifts the equilibrium to the right according to Le Chatelier’s principle.

Ans 2:

  • According the balanced chemical equation for esterification, 1 mol of acetic acid demands 1 mol of 1-propanol (1:1 ratio). (refer the equation given in the question)

Molar mass, M

density, d = m/V

Volume taken, V

Mass taken (m)

Mole taken

m/M

Remark

Acetic acid

CH3COOH

60.052 g/mol

1.049 g/ml

25 ml

26.225 g

0.4367 mol

Acetic acid is taken in excess

CH3COOH: C3H7OH = 1.46:1

1-propanol

C3H7OH

60.09 g/mol

0.900 g/ml

20 ml

18.00 g

0.2996 mol

  • One of the reactant taken in excess also helps in pushing the equilibrium to the right increasing the product yield according to Le Chatelier’s principle.

Ans 3:

Using Dean–Stark apparatus one can easily remove water as soon as it forms.

It is a piece of laboratory glass apparatus used to collect water from a reaction vessel. It is used along with a reflux condenser and a batch reactor for removal of the water as soon as it is formed during a chemical reaction performed at reflux temperature.

Ans 4:

  • Moles of acetic acid taken: 0.4367 mol
  • Moles of 1-propanol taken: 0.2996 mol
  • Limiting reagent (reagent which is in less amount than required) of the reaction: 1-propanol.
  • Theoretically, during the reaction limiting reagent will be completely consumed to become the product. Accordingly, 1-propanol will be completely consumed.
  • According the balanced chemical equation (refer the equation in question), 1 mol of 1-propanol gives 1 mol of ester i.e n-propylacetate (CH3COOC3H7). So, 0.2996 mol of 1-propanol should form 0.2996 mol of ester.
  • Molar mass of ester (n-propylacetate): 102.131 g/mol
  • Mass of 0.2996 mol of ester = 102.131 x 0.2996 = 30.5984 g

Theoretical yield of ester = 0.2996 mol = 30.5984 g

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