Solution:
13) Option E
Ionic radius increases when we move from up to down in a group.
Ionic radius of same period elements increases with increasing negative charge and decreases with increasing positive charge.
A negatively charged ion has lesser number of protons in nucleus, therefore nucleus exerted weak attraction to the electrons and increases the size. The positively charged ions posses smaller size due to high nuclear charge which causes strong attraction.
15) Option D
This question can be solved by simple thinking. The sigma 2s and sigma 2s* molecular orbitals are lying above the sigma 1s and sigma 1s* orbitals, hence they posses higher energy than lower orbitals.
Thus, option will be D because other options are smaller than or equal to 3.44 x 10^-21 J.
Note : Energy difference can not be zero between excited and nonexcited state.
Part C)
The calculated frequency in part B is low, hence can not perform excitation given in higher orbital excitations of part A.
please help urgent ( will rate) hi the answer to these questions are ones ive circles...
Please help urgent( will rate):) hi so the right answer to these questions are the ones ive circled but i just dont understand why. thanks the answer to 15 is D 28 6. He ions are prepared with the electron in the T=X state. The electrons relax to lower energy states, by one or more transitions, and produce an emission spectrum with light at 6 difference wavelengths. What is the value of X? A. 3 B. 4 С. 5 D....
What is the coefficient of H.So, when the following equation is properly balanced with the smallest set of whole numbers? __Cas(PO4h + H2SO4 - Caso + HPO. A) 3 B) 8 C) 10 D) 11 2) What is the coefficient of H20 when the following equation is properly balanced with smallest set of whole numbers? ALC + H2O - AM(OH), + CHE A) 3 B) 4 C) 6 D) 12 E) 24 3) of the reactions below, which one is...