Question

points CJ6 2 P (a) What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 6.6 ms when going down a slope for 2.6 s7 b) How far does the skier travel in this time?
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Answer #1

This question is based on the concept of

1. Average acceleration

2. Newton's eqn of motion.

The detailed solution is described below

Sslukion Let w to the bapics fat t= 26 s ng = ? We know仇at ay, acceleratin -t 2.6S () distance toeskier distance tov elled . ら6.62= 02-+ 2*4538 * S aKS

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