Question

ASD Daniele Hore 1.) ALCOH)₂ + 3HCL AC + 3H₂O1 3 grams mixed with 40 mL of 0.25 M HCl, which is Limiting reagent? 11 Find it of mores (0.25 0.0ML) Coolmol ten (3 grams Jl mal Toomal Hut 789 0.003 Aici How many moisso (0.38 moi AICOW) = 0.30 mal Alchz Theamtical =) How much product can be formed from 6.) (0.003 mol HCl). 3 -0.001 mol Alcza 3 HCl - Theoretical yisid in oies. (0.003 mol ) AICH - Xa : Theoretical vieid in mol oxidationt element losses electrons toxd # 1

Answer 1

Al GHz + 3 Hd Allz + 3 H20 a) moles of All but) = mama.com moles of Hel = Mxv a 0:25*( 40 ) 70.0386 mden 0.0 moles :) I mole of All(OH), gives - I mole of Alla 0.0385 moles of Al (GH), geves → 18010385 *000385 moles of Alelz ii) 3 moles of He gives I mole of Alla 0.01 moles of Hc gives > 1X0.01 10:0033 moles of Ally 3 * Hel is the limiting reagent, as it controls the product formation. - b) moles of Alda ferred =0.0033 moles mais of Alls (Theoretical gield) formed = molesx molarmans FO00 33* 133134 0.449 c) oxidation lors of electrons is called as oxidation,