On reactant side we have:
2 C≡O bond
1 O=O bond
On product side we have:
4 C=O bond
Use:
Delta H = BE(reactant) - BE(product)
= 2*BE(C≡O) + 1*BE(O=O) - 4*BE(C=O)
= 2*1073 + 1*498 - 4*803
= -568 KJ
Answer: -568 KJ
QUESTION 1 Calculate the heat of reaction (energy of reaction) in kJ/mol for the following reaction....
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