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3. A plan for an executive travelers club has been developed by an airline on the premise that 10% of its current customers

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Answer #1

a) n = 25

    p = 0.1

P(2 < X < 4)

= P(X = 2) + P(X = 3) + P(X = 4)

= 25C2 * (0.1)^2 * (0.9)^23 + 25C3 * (0.1)^3 * (0.9)^22 + 25C4 * (0.1)^4 * (0.9)^21

= 0.6308

b) Expected value = np = 100 * 0.1 = 10

   Standard deviation = sqrt(np(1 - p))

                               = sqrt(100 * 0.1 * 0.9)

                               = 3

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