Homework Answers
8) 5 mole O2 give 531 Kcal energy
3 mole O2 give 531×3/5 Kcal energy
= 318.6 Kcal
10) a) K = [PCl5]/[PCl3][Cl2]
b) K = [SO3]2/[SO2]2[O2]
c) K = [HBr]2/[H2][Br2]
d) K = [CHCl3][HCl]3/[CH4][Cl2]3
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Draw an energy diagram for a reaction with a high E. and the enthalpy change of...
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking...
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize 3rd attempt See Hint Ad See Periodic Table Part 1 (1 point)...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize Part 1 (1 point) Il See Periodic Table...
8. The standard reaction enthalpy for the hydrogenation of propene, CH-CHCH2 + 5 02 → CH3CH2CH3p....
8. The standard reaction enthalpy for the hydrogenation of propene, CH-CHCH2 + 5 02 → CH3CH2CH3p. is 124.0 kJ/mol. The standard reaction enthalpy for the formation of water, H ( + 7 O2(g) → H2O).is -286.0 kJ/mole. The standard reaction enthalpy for the combustion of propane, CH3CH2CH3 +5 O2(g) → 3 CO2 + H2O() is 2220 kJ/mol. Calculate the standard enthalpy of reaction for propene. (ANS: -2058 kJ/mol)
The standard enthalpy change for the following reaction is 1.16x103 kJ at 298 K. 2 CrO3(s)...
The standard enthalpy change for the following reaction is 1.16x103 kJ at 298 K. 2 CrO3(s) — 2 Cr(s) + 3 O2(g) AH° = 1.16x103 kJ What is the standard enthalpy change for this reaction at 298 K? Cr(s) + 3/2 O2() Cro33) Ethanol, C2H50, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is a renewable resource and ethanol-blended fuels, like gasohol, appear to burn more efficiently...
7 a. Draw a reaction energy diagram for the following reaction and label Eaforward with its...
7 a. Draw a reaction energy diagram for the following reaction and label Eaforward with its correct value A(g) + B (g) C(g)+ D(g) AH=45 kj/mol Eareverse is 56 kj/mol b. Is the forward reaction exothermic or endothermic? c. Use this energy diagram to fully describe what a catalyst would do. Tor d. Using protein digestion and chymotrypsin, describe how enzymes act as catalysts.
CHEM 212 Practice Sheet la) Sketch an energy diagram for a chemical reaction that is exothermic...
CHEM 212 Practice Sheet la) Sketch an energy diagram for a chemical reaction that is exothermic (AH--200 kJ/mol. The reaction is single-step and has an activation energy of 100 kJ/mol. 1b) Now, draw an energy diagram for the same chemical reaction upon addition of a catalyst. 2) At 1000 K, K, -1.85 for the reaction SO, (g) + 0(8) SO, (g) a) Write an expression for the equilibrium constant, K b) What is the value of K, for the reaction...
calculate the standard free energy change for the following reaction Pb(l) + 1/2 O2(g) = PbO(s)...
calculate the standard free energy change for the following
reaction Pb(l) + 1/2 O2(g) = PbO(s) at 527 C
(EBB 160 -7- [b] Calculate the standard free energy change for the following reaction Pb (I)+ 2 O2 (g)-PbO (s) at 527°C given the following data AH 298 PhOUS)-220,080 J/mol AH R00 PROUS 220,424,4-JHmot 8 k ASo 298,PbO(S)=68.04 JIKImol AS 298,Ph(8)65.1 JIKImol 205.88 J/KImol AS 298,02(g) SG.Cn /K/mol CP PHOS)=44.52 +16.8x10 JIK/mol V Cp.Phe)=23.65+9.79x10( K/mol Cp Pory=32.55-3.108x10 1.68x10% Croe)=30.07+4.2x10 JIKImol 327°C...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of Nz(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.1 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst:. IN,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 7. Use these data...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of N2(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst: [N,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 0.1 7. Use these data...
Draw the Born-Haber Cycle with these values and calculate lattice energy. Problem 1: Label each reaction...
Draw the Born-Haber Cycle with these values and calculate
lattice energy.
Problem 1: Label each reaction listed below for the Born-Haber cycle in the formation of Cao lattice and calculate the lattice energy of Cal given the following information. AH KD) Ca(s) + Ca(8) 193 Calg) - Cat (8) + e 590 Cat (8) - Cat (8) + e- 2 O(g) + O2(g) O(8) + e- O (8) -141 O (8) + e- O (8) 878 Ca(s) + O2(g) →...
The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize 3rd attempt See Hint Ad See Periodic Table Part 1 (1 point)...
13 Question (3 points) The enthalpy change for a chemical reaction is the sum of the energy consumed in breaking bonds and the energy released during bond formation. One way to determine the overall energy change for a chemical reaction is to apply Hess's law to add together a group of reactions which can be arranged such that the chemical equations, when combined, give the overall equation we are trying to characterize Part 1 (1 point) Il See Periodic Table...
8. The standard reaction enthalpy for the hydrogenation of propene, CH-CHCH2 + 5 02 → CH3CH2CH3p. is 124.0 kJ/mol. The standard reaction enthalpy for the formation of water, H ( + 7 O2(g) → H2O).is -286.0 kJ/mole. The standard reaction enthalpy for the combustion of propane, CH3CH2CH3 +5 O2(g) → 3 CO2 + H2O() is 2220 kJ/mol. Calculate the standard enthalpy of reaction for propene. (ANS: -2058 kJ/mol)
The standard enthalpy change for the following reaction is 1.16x103 kJ at 298 K. 2 CrO3(s) — 2 Cr(s) + 3 O2(g) AH° = 1.16x103 kJ What is the standard enthalpy change for this reaction at 298 K? Cr(s) + 3/2 O2() Cro33) Ethanol, C2H50, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is a renewable resource and ethanol-blended fuels, like gasohol, appear to burn more efficiently...
7 a. Draw a reaction energy diagram for the following reaction and label Eaforward with its correct value A(g) + B (g) C(g)+ D(g) AH=45 kj/mol Eareverse is 56 kj/mol b. Is the forward reaction exothermic or endothermic? c. Use this energy diagram to fully describe what a catalyst would do. Tor d. Using protein digestion and chymotrypsin, describe how enzymes act as catalysts.
CHEM 212 Practice Sheet la) Sketch an energy diagram for a chemical reaction that is exothermic (AH--200 kJ/mol. The reaction is single-step and has an activation energy of 100 kJ/mol. 1b) Now, draw an energy diagram for the same chemical reaction upon addition of a catalyst. 2) At 1000 K, K, -1.85 for the reaction SO, (g) + 0(8) SO, (g) a) Write an expression for the equilibrium constant, K b) What is the value of K, for the reaction...
calculate the standard free energy change for the following
reaction Pb(l) + 1/2 O2(g) = PbO(s) at 527 C
(EBB 160 -7- [b] Calculate the standard free energy change for the following reaction Pb (I)+ 2 O2 (g)-PbO (s) at 527°C given the following data AH 298 PhOUS)-220,080 J/mol AH R00 PROUS 220,424,4-JHmot 8 k ASo 298,PbO(S)=68.04 JIKImol AS 298,Ph(8)65.1 JIKImol 205.88 J/KImol AS 298,02(g) SG.Cn /K/mol CP PHOS)=44.52 +16.8x10 JIK/mol V Cp.Phe)=23.65+9.79x10( K/mol Cp Pory=32.55-3.108x10 1.68x10% Croe)=30.07+4.2x10 JIKImol 327°C...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of Nz(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.1 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst:. IN,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 7. Use these data...
The reaction can be speeded up by using a catalyst that reduces the activation energy. The most popular catalysts are based on iron (Fe) and ruthenium (Ru). The table shows the variation in the concentration of N2(g) as a function of time for a reaction carried out at 500 °C and 200 atm in the presence 0 0.2 0.3 0.4 0.5 0.6 of an Fe catalyst: [N,(e)] (mol/L) 2.00 1.68 1.42 1.19 1.01 0.846 0.710 0.1 7. Use these data...
Draw the Born-Haber Cycle with these values and calculate
lattice energy.
Problem 1: Label each reaction listed below for the Born-Haber cycle in the formation of Cao lattice and calculate the lattice energy of Cal given the following information. AH KD) Ca(s) + Ca(8) 193 Calg) - Cat (8) + e 590 Cat (8) - Cat (8) + e- 2 O(g) + O2(g) O(8) + e- O (8) -141 O (8) + e- O (8) 878 Ca(s) + O2(g) →...
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