Molar mass of PbSO4 = 303.26 g/mol
mass(PbSO4)= 0.0183 g
use:
number of mol of PbSO4,
n = mass of PbSO4/molar mass of PbSO4
=(1.83*10^-2 g)/(303.26 g/mol)
= 6.034*10^-5 mol
volume , V = 4.8*10^2 mL
= 0.48 L
use:
Molarity,
M = number of mol / volume in L
= 6.034*10^-5/0.48
= 1.257*10^-4 M
This is solubility of PbSO4
At equilibrium:
PbSO4 <----> Pb2+ + SO42-
s s
Ksp = [Pb2+][SO42-]
Ksp = (s)*(s)
Ksp = 1(s)^2
Ksp = 1(1.257*10^-4)^2
Ksp = 1.58*10^-8
Answer: 1.58*10^-8
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