solution:- option B) 0.99 < σ < 1.90
given that n = 20 ,
mean = 2.4 , standard deviation s = 1.3
95% confidence and with df = 20 - 1 = 19
=>X^2 distribution
=> X^2 R = 32.85
=> X^2 L = 8.907
formula
=> sqrt((n-1)* s^2 /X^2 R) < σ < sqrt((n-1)* s^2 /X^2 L)
=> sqrt(20-1)* 1.3^2 /32.85) < σ < sqrt(20-1)* 1.3^2 /8.907)
=> sqrt(19*1.69/32.85) < σ < sqrt(19* 1.69 /8.907)
=> 0.99 < σ < 1.90