Homework Answers
No.of moles of Na2 CO3= mass/ mol.mass= 0.19/106= 0.00179
Na2CO3+2HCl---->2NaCl+H2O+CO2
No.of moles of HCl=2x0.00179=0.00358
Eq.volume of HCl = data is insufficient, plot is missing.
Soda ash is the common name for Sodium carbonate.Hence similarly we can calculate the number of moles.But we can't calculate the volume as the plot is not available
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ch graphs Standardization of Hydrochloric Acid: Weight of container + Na2cO3 20-0621g Weight of container 19-896tg...
Analysis of an Unknown Soda Ash Sample: Unknown sample number #7 Weight of container +unknown 20.2168...
Analysis of an Unknown Soda Ash Sample: Unknown sample number #7 Weight of container +unknown 20.2168 g Weight of container 19.8867 g Weight of unknown soda ash nown soda ash 0.33019 Equivalence Volume of HCI 1805 mL (Equiv. volume from plot minus initial volume HCI) Moles of HCI Moles of Na2CO3 in unknown Grams of Na2CO3 in unknown % Na2CO3 in soda ash
DAY_ _INS LABORATORY REPORT FOR Part I Standardization of NaOH Trial 1 Weight of bottle +...
DAY_ _INS LABORATORY REPORT FOR Part I Standardization of NaOH Trial 1 Weight of bottle + "KHP" 21.5350 Weight of bottle 20.7995 Weight of "KHP" used 0.8055 Equiv. Volume of NaOH from plot 3125 Equivalence Volume of NaOH 3125 (Equiv. Volume NaOH from plot minus initial volume NaOH) Molarity of NaOH 0.126 Average Molarity 0.126 M Part II - Titration of a Weak Acid Unknown weak acid code Trial 1 Trial 2 Volume of unknown acid 25.00 Equiv. Volume of...
5.119 A 24.9-mL volume of hydrochloric acid reacts com pletely with 55.0 mL of aqueous Na2CO3....
5.119 A 24.9-mL volume of hydrochloric acid reacts com pletely with 55.0 mL of aqueous Na2CO3. The reaction is 2HCI(aq) NaCO3(aq) CO2(g) + H20() + 2NaCl(ag) The volume of CO, formed is 141 mL at 27°C and 727 mmHg. What is the molarity of the HCl solution? 5.120 A 21.4-mL volume of hydrochloric acid reacts com- pletely with a solid sample of MgCO3. The reaction is 2HCI(aq)MgCO3(s) CO2(g) + H2O() + MgCl (ag) The volume of CO, formed is 159...
Experiment 6: The Standardization of a Basic Solution and the Determination of the MM of an Acid
Experiment 6: The Standardization of a Basic Solution and the Determination of the MM of an Acid *Note: This experiment is relatively long unless you know precisely what to do. Read the experiment before coming to class and arrive on time. After reading through the experiment answer the following question: 1. 7.0 mL of 6.0 M NaOH are diluted with water to a volume of 400 mL. You are asked to find the molarity of the resulting solution. a. First find out how many...
This is my data! How to do all the calculations and everything in lab report? 3...
This is my data! How to do all the calculations and everything
in lab report?
3 A. Standardization of NaOH Solution Trial 1 Trial 2 Trial 3 6 Initial burette reading, HCI 7 Final burette reading, HCI 8 Initial burette reading, NaOH 9 Final burette reading NaoH 10 11 B. Determination of the Molar Mass of an Unknown Acid 12 13 Mass of vial plus contents 14 Mas of vial plus contents less Sample 1 mL mL mL mL mL...
Sodium carbonate, Na2CO3, reacts with hydrochloric acid, HCl, to produce sodium chloride, carbon dioxide and water....
Sodium carbonate, Na2CO3, reacts with hydrochloric acid, HCl, to produce sodium chloride, carbon dioxide and water. Refer to slide 7.18 for a summary of formulae relevant to the calculations below. 2HCl(aq) + Na.CO3(aq) + NaCl(aq) + H2O(l) + CO2(g) 1. Use this reaction to explain what is meant by the terms "acid", "conjugate base" and "salt" 2. Balance the equation for this reaction. 3. A solution was prepared by dissolving 5.00 g of Na2CO3 in water and adding water to...
ratra 1z 1 t B: Detes Name Date inoe Acid-Base Titration Data and Calculations Part A:...
ratra 1z 1 t B: Detes Name Date inoe Acid-Base Titration Data and Calculations Part A: Standardization of NaOH solution, Data: Trial 1 Trial 3 Trial 2 Initial level, HCI buret 26-60 mL Final level, HCI buret 33.85 mL 43.15 2u.95 mL mL Initial level, NaOH buret 00mL Final level, NaoH buret 23.45 mL 44.35 mL 24.25 mL Calculations: Trial 1 Trial 2 Trial 3 Total volume HCI solution 24.45 mL 33-86 mL 43.95 mL 0.1030 Molarity of standardized HCI...
The Na,Co, solution described above was used to analyse a hydrochloric acid solution of unknown concentration....
The Na,Co, solution described above was used to analyse a hydrochloric acid solution of unknown concentration. It was found that 24.30 mL of the Na,Co, solution was required to neutralise a 20.00 mL sample of the hydrochloric acid solution. 4. Using your answer to part 3 above, calculate the amount of Na,Co, present in 24.30 mL of the Na,Co, solution. (2 marks) 5. Using your answer to part 2 above, deduce the amount of HCl that was present in the...
The following primary standards can be used for the standardization of bases except. a. Benzoic acid...
The following primary standards can be used for the standardization of bases except. a. Benzoic acid b. Oxalic acid c. CaCO3 d. KHP A solution that may contain NaOH, Na 2CO3, and NaHCO3, alone or in compatible combination was titrated with 0.1200 M HCl. The volume of the acid required to reach the phenolphthalein endpoint was 25.67 mL while 38.13 mL to reach the methyl red endpoint. What are the components of the mixture? a. Na2CO3 only b. NaOH only...
n this exercise, weighed samples of a solid unknown containing NaCl and NaHCO3 react with hydrochloric...
n this exercise, weighed samples of a solid unknown containing NaCl and NaHCO3 react with hydrochloric acid. The volume of the CO2 liberated by the reaction in the gas phase is measured with a gas collection syringe. From the volume we can calculate the number of moles of CO2 in the gas phase using the ideal gas approximation. Since the CO2 is generated in an aqueous environment (aqueous HCl), some CO2 will dissolve in the liquid phase. The amount of...
Analysis of an Unknown Soda Ash Sample: Unknown sample number #7 Weight of container +unknown 20.2168 g Weight of container 19.8867 g Weight of unknown soda ash nown soda ash 0.33019 Equivalence Volume of HCI 1805 mL (Equiv. volume from plot minus initial volume HCI) Moles of HCI Moles of Na2CO3 in unknown Grams of Na2CO3 in unknown % Na2CO3 in soda ash
DAY_ _INS LABORATORY REPORT FOR Part I Standardization of NaOH Trial 1 Weight of bottle + "KHP" 21.5350 Weight of bottle 20.7995 Weight of "KHP" used 0.8055 Equiv. Volume of NaOH from plot 3125 Equivalence Volume of NaOH 3125 (Equiv. Volume NaOH from plot minus initial volume NaOH) Molarity of NaOH 0.126 Average Molarity 0.126 M Part II - Titration of a Weak Acid Unknown weak acid code Trial 1 Trial 2 Volume of unknown acid 25.00 Equiv. Volume of...
5.119 A 24.9-mL volume of hydrochloric acid reacts com pletely with 55.0 mL of aqueous Na2CO3. The reaction is 2HCI(aq) NaCO3(aq) CO2(g) + H20() + 2NaCl(ag) The volume of CO, formed is 141 mL at 27°C and 727 mmHg. What is the molarity of the HCl solution? 5.120 A 21.4-mL volume of hydrochloric acid reacts com- pletely with a solid sample of MgCO3. The reaction is 2HCI(aq)MgCO3(s) CO2(g) + H2O() + MgCl (ag) The volume of CO, formed is 159...
This is my data! How to do all the calculations and everything
in lab report?
3 A. Standardization of NaOH Solution Trial 1 Trial 2 Trial 3 6 Initial burette reading, HCI 7 Final burette reading, HCI 8 Initial burette reading, NaOH 9 Final burette reading NaoH 10 11 B. Determination of the Molar Mass of an Unknown Acid 12 13 Mass of vial plus contents 14 Mas of vial plus contents less Sample 1 mL mL mL mL mL...
Sodium carbonate, Na2CO3, reacts with hydrochloric acid, HCl, to produce sodium chloride, carbon dioxide and water. Refer to slide 7.18 for a summary of formulae relevant to the calculations below. 2HCl(aq) + Na.CO3(aq) + NaCl(aq) + H2O(l) + CO2(g) 1. Use this reaction to explain what is meant by the terms "acid", "conjugate base" and "salt" 2. Balance the equation for this reaction. 3. A solution was prepared by dissolving 5.00 g of Na2CO3 in water and adding water to...
ratra 1z 1 t B: Detes Name Date inoe Acid-Base Titration Data and Calculations Part A: Standardization of NaOH solution, Data: Trial 1 Trial 3 Trial 2 Initial level, HCI buret 26-60 mL Final level, HCI buret 33.85 mL 43.15 2u.95 mL mL Initial level, NaOH buret 00mL Final level, NaoH buret 23.45 mL 44.35 mL 24.25 mL Calculations: Trial 1 Trial 2 Trial 3 Total volume HCI solution 24.45 mL 33-86 mL 43.95 mL 0.1030 Molarity of standardized HCI...
The Na,Co, solution described above was used to analyse a hydrochloric acid solution of unknown concentration. It was found that 24.30 mL of the Na,Co, solution was required to neutralise a 20.00 mL sample of the hydrochloric acid solution. 4. Using your answer to part 3 above, calculate the amount of Na,Co, present in 24.30 mL of the Na,Co, solution. (2 marks) 5. Using your answer to part 2 above, deduce the amount of HCl that was present in the...
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