pKb of trimethyl amine = 4.19 (Literature value)
we have
0.500 M of trimethylamine
this is weak base.
so
Using
pOH = 1/2 * [pKb - log (C)]
pOH = 1 / 2 * [4.19 - log (0.500) ]
or
pOH = 4.49
we know,
pH + pOH = 14
or
pH = 14 - 4.49 = 9.51
thus
PH of 0.500M of trimethylamine = 9.51
what is the pH value of 0.500M of trimethylamine ? = Objective Knowledge Check Acetic acid...
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