Question

In Exercises 1-8, find the indicated area under the standard normal curve. If convenient, use technology to find the area 1. To the right of z-3.2:2 2. To the left of z--2.825 3. To the right ofz-0.015 4. Between 1.64 and z-0 5. Between 6. Between z=0.05 and z=1 .71 7. Between z=-2.68 and z=2.68 8. To the left of z--1.5 and to the right of z-1.5 1.55 and z-1 In Exercises 9-15, find the indicated probability using the standard normal distribution 9. P(z<1.28) 10. Pz-0.74) 11. P(-2.15<1.55) 12. P(0.42-г<31 5) 13. Plz<-2.50 or z>2.50) 14. Pz<0 or z>1.68) 15. Yearly amounts of black carbon emissions from cars in India are normally distributed, with a mean of 14.7 gigagrams per year and a standard deviation of 11.5 gigagrams per year. Find the probability that the amount of black carbon emissions from cars in India for a randomly selected year are (a) less than 12.3 gigagrams per year| (b) between 15.4 and 19.6 gigagrams per year (c) greater than 17.7 gigagrams per year. (Adapted from Atmospheric Chemistry and Physics)

Answer 1

(1) Area = 0.0006

(2) Area = 0.0024

(3) Area = 0.4940

(4) Area = 0.4495

(5) Area = 0.7903

(6) Area = 0.4364

(7) Area = 0.9926

(8) Area = 0.0668 + 0.0668 = 0.1336