Question

The figure below shows the positions of two alpha particles (each alpha particle has a charge +2e and an electron. a) Draw a clear and neat free-body diagram for either sphere at equilibrium.

b) Determine the magnitude and direction of the resultant force on the electron. (Hint: Choose the +x-axis along the line from the electron to the right-hand  particle.)

c) Determine the acceleration of the electron due to the net force acting on it. The mass of the electron is me=9.11×10^-31 kg.

0C 3.50 × 10-1m\ \ ,/2.10 × 10 10 m 53лу

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Answer #1

+2e чух 6= 53.1° 3.5 x 10 m +2e 2.1X10 m Fa= K Cex 2e) (2-1X10-1032 K(ex 2e) C3.5 x10-10)2 = 9x10x 2x CI.6X1019,2 ;x cos 53.

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