An object of mass m is at rest at the top of a smooth slope of height h and length L. The coefficient of kinetic friction between the object and the surface, μk, is small enough that the object will slide down the slope if given a very small push to get it started.Sam, whose mass is 75 kg , stands at the top of a 14-m-high, 90-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom?
Sam Whose mass is 100 kg stands at the top of a 18-m-high, 120-m-long snow covered slope, His skis have a coefficient of kinetic friction on snow of 0.06. He uses his poles to get started. then glides down. 1. The value closest to the normal force acting on Sam is a. 729.7 N b. 735.0 N c. 968.9 N d. 980.0 N 2. The net force acting on Sam is a. 37.1 N b. 88.9 N c. 147 N...
Sam, whose mass is 70.0 kg , takes off down a 45.0 m high, 12.0 ∘ slope on his jet-powered skis. The skis have a thrust of 180 N . Sam's speed at the bottom is 40.0 m/s .What is the coefficient of kinetic friction of his skis on snow?
Josh starts his sled at the top of a 2.0 m-high hill that has a constant slope of 25 degrees . After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.07.
A skier on a slope inclined at 4.7° to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7 m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to res
A skier with mass 64.0 kg starts at rest at the top of an 842 m long ski slope, which makes an angle 13.0 ∘ with the horizontal. A typical coefficient of friction between skis and snow is 5.20×10−2. skiers don't go straight down the hill- they zigzag back and forth. Even though they still end up at the bottom of the hill, they've lost more energy to friction because friction is a non-conservative force. Let's say due to zigzagging,...
A 31 kg boy on a 4 kg sled is at the top of a slope that is 6 m high. He slides down the snow-covered, frictionless slope and across a road that is 8 m wide and then up a driveway at an angle of 15o. Both the road and the driveway have a coefficient of kinetic friction k = 0.36. How far does the boy slide up the driveway before he comes to a stop?
(5 points) A box of mass m is released from rest at the top of a slope of length L at angle θ above the ground. The coefficient of kinetic friction between the box and the slope is μk. (a) (2 points) Draw a figure for the problem, and the free body diagram. and solve for the net forces (b) (1 point) Solve for the net forces along the two axes. (c) (1 point) Solve for acceleration down the slope...
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Jam Whose mass is 100 kg stands at the top of a 18-m-high, 120-m-long sa His skis have a coefficient of kinetic friction on snow of 0.06. He uses his poles to get then glides down. of a 18-m-high, 120-m-long snow covered slope. 1. The value closest to the normal force acting on Sam is a. 729.7 N b. 735.0 N c. 968.9 N d. 980.0 N 2. The net force acting on Sam...
- Problem Solving (40 points total, 10 points each) 12. A 75-kg skier stands at rest atop a hill. The coefficient of friction between the skis and snow is 0.06. The skier glides down the length of the hill to its bottom. What is the skier's velocity at the bottom of the hill? L = 32.5 m O = 40°
An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0° with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts down a distance of 12.1 m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point whose vertical distance is 2.60 m below the edge. How fast is she going just before she...