Homework Answers
We hall check whether T(x)=T(y) under y=(9/5)x+32.
Now under y=(9/5)x+32, T(y)=.5*(9x/5+32)+.5*(212)
=9x/10+16+106
=9x/10+122=.9x+122,
which is different from T(y). Hence the process is not estimation equivariant.
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