Question

Three spiders are resting on the vertices of a triangular web. The sides of the triangular web have a length of a = 0.53 m, as depicted in the figure. Two of the spiders (S1 and S3) have +6.8 μC charge, while the other (S2) has-6.8 μc charge. a/2 s, 1/2 S2 (a) What are the magnitude and direction of the net force on the third spider (S3)? magnitude 0,4357 direction How do you find the magnitude of the electric force? How do you find the total net force? N 。counterclockwise from the +x-axis (b) Suppose the third spider (S3) moves to the origin. Would the net force on the third spider (S3) be greater than, less than, or equal to the magnitude found in part (a)? greater than in part (a) O less than in part (a) O equal to the part (a) (c) What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin? magnitude direction counterclockwise from the +x-axis

Answer 1

a) The magnitude of the net force on the third spider S_3 is, F_3 = k q_1 q_2/a^2 = (9 times 10^9) (2) (6.8 times 10^-6)^2/(0.53)^2 cos 60 = 1.48 N = 1.5 N The direction is 270 degree downward b) The net force on the spider is greater than the magnitude found in part of a c) The magnitude of the net force on third spider at the origin is, F_3 = K q_1 q2/a^2 = (9 times 10^9) (2) (6.8 times 10^-6)^2/(0.53/2)^2 = 11.85 N = 12 N The direction is 270 degree downward