Using the formula PV = nRT
Here, P = 755 mmHg = 0.9934 atm
V = 260 mL = 0.26 L
T = 273 + 28 = 301 K
R = 0.082 L.atm/K.mol
Now using the above relation.
n = (0.9934 x 0.26)/(0.082 x 301) = 0.0105 mol
Now 1 mol of N2O4 contains = 6.022 x 1023 molecules
0.0105 mol of N2O4 contains = 0.0105 x 6.022 x 1023 molecules = 6.322 x 1021 molecules
Now 1 molecule of N2O4 contains number of nitrogen = 2
6.322 x 1021 molecules of N2O4 contains number of nitrogen = 2 x 6.322 x 1021 = 1.2644 x 1022
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